shell - Case statement not working -

its part of program,

output="$(./t1)"        // output=5  echo $output            // displays 5  if test $output -eq 5 echo "five"             // if statement works , displays 'five' fi  case $output in          **// case not working , giving default value**  1) echo "one" ;;  2) echo "two" ;;  3) echo "three" ;;  4) echo "four";;  5) echo "five";;  *) echo "wrong choice" ;;  esac                    // output wrong choice though works proper in if statement    

is there mistake in bash script? please help.

this works me:

output=$(./t1) echo $output if test $output -eq 5; echo "five"; fi case $output in   1) echo "one" ;;   2) echo "two" ;;   3) echo "three" ;;   4) echo "four";;   5) echo "five";;   *) echo "wrong choice" ;; esac 

when had " around $(./t1) result string, not numeric value. worked test, not case. has couple of missing ; in post , // not valid comments in bash.