optimization - How to quickly replace many matching items with a single replacement in BASH? -

i have file, "items.txt" containing list of 100,000 items need remove file "text.txt" , replace "111111111".

i wrote script works intend:

#!/bin/bash a=0 b=`wc -l < ./items.txt` while read -r line     a=`expr $a + 1`     sed -i "s/$line/111111111/g" text.txt     echo "removed ("$a"/"$b")." done < ./items.txt 

this script looks @ eat line in "items.txt", uses sed remove each line "text.txt".

this script slow though. estimate, take more 1 week remove of items file on computer. there more efficient way replace of items quickly?

bash 4.1.5

use sed build sed script replace items:

sed 's/^/s=/;s/$/=111111111=g/' items.txt | sed -f- text.txt 

update: following perl script seems faster:

#!/usr/bin/perl use warnings; use strict;  open $items, '<', 'items.txt'; @items = <$items>; chomp @items; $regex = join '|', @items; $regex    = qr/$regex/;  open $text, '<', 'text.txt'; while (<$text>) {     s/$regex/111111111/g;     print; }