r - open many file in one time and each store as one dataframe -

i have many data in 1 folder

data=list.files(path="d:/result") 

data

> > [1] "cnvworkshop (1).txt" "e17 result.txt"       [3] "e17new result.txt"   "e18 new result.txt"  >  >  [5] "e18result.txt"       "l15 new result.txt"    [7] "l15 > result.txt"      "l22new result.txt"    [9] "l51 new result.txt"  > "l51result.txt"       [11] "l54 new result.txt"  "l54result.txt"       > [13] "penncnv.txt"         "s40 new result.txt" 

i want read many file in 1 time , store each file each dataframe

a=paste("watto",1:14,sep="") 

this things below it's not work

for(i in 1 :length(data)){   a[i]=read.table(file=paste("d:/result/",data[i],sep=""),header=t,sep="\t")  } 

and it's show warning message , not give me result

> warning message: in a[1] = read.table(file = paste("d:/result/", data[1], sep = ""),  :   number of items replace not multiple of replacement length 

the result want is

> data watto1 come cnvworkshop (1).txt  > data watto2 come e17 result.txt 

how should do?

try:

   <- lapply(data, function(x) read.table(file=paste0("d:/result/",x),     header=true, sep="\t") ) 

you're getting error message because of r's subsetting rules. when assign single brackets a[1] <-, r expects replacement of same length 1. a[c(1,2)] <- r accepts replacement values of length 2, , on. data frame has length (being number of columns) greater 1 , being rejected.

you instead specify replacing list element (note double-brackets:

for(i in 1 :length(data)){   a[[i]]=read.table(file=paste("d:/result/",data[i],sep=""),     header=true,sep="\t")  } 

however, not r-like syntax. iterative tasks not rely on recursion can performed via lapply family of functions.