Displaying Hjighest and Lowest number in C++ -

i trying way. seems more simplified. trying figure out how include month names , program output name of rainiest month not number user inputs.

#include <iostream> #include <conio.h>  using namespace std; int main () {     int a[12];      int x;     (x=0; x<12; x++)     {         cout << "insert days of rainfall month "<<x+1<<endl;         cin >>a[x];     }     int max;     int min;     max = a[0];     min = a[0];     int e=0;     while (e<12)     {         if (a[e]>max)         {              max = a[e];         }         else if (a[e]<min)         {             min = a[e];         }         e++;         cout<<"the rainiest month " <<max<<endl;         cout<<"the least rainy month " <<min<<endl;         getch ();         return 0;     }       system("pause");     return exit_success; } 

your average calculation off little, have take consideration order of operations when comes math. multiplication , division done first, addition , subtraction. end dec divided 12, , add other days it. fix this, need wrap additions of of months in parentheses force addition happen first, divide after. in case, can use year variable since of months added , divide 12.

as far question goes, want show highest , lowest values input, don't see attempt solve in code. feel less inclined write code give brief explanation of need instead. @ value each month, each time @ next month, compare current highest , current lowest values remember. when new month has new higher, or new lower, value replace value remember. once cycle through every month end highest , lowest values.