python - How to open every file in a folder? -

i have python script parse.py, in script open file, file1, , maybe print out total number of characters.

filename = 'file1' f = open(filename, 'r') content = f.read() print filename, len(content)

right now, using stdout direct result output file - output

python parse.py >> output

however, don't want file file manually, there way take care of every single file automatically? like

ls | awk '{print}' | python parse.py >> output

then problem how read file name standardin? or there built-in functions ls , kind of work easily?

thanks!

you can list files in current directory using:

import os filename in os.listdir(os.getcwd()):    # stuff

or can list files, depending on file pattern using glob module:

import glob filename in glob.glob('*.txt'):    # stuff

it doesn't have current directory can list them in path want:

path = '/some/path/to/file'  filename in os.listdir(path):     # stuff  filename in glob.glob(os.path.join(path, '*.txt')):     # stuff

or can use pipe specified using fileinput

import fileinput line in fileinput.input():     # stuff

and use piping:

ls -1 | python parse.py

Detect