C Program Not Compiling -

i need find largest number (which double). problem in program? isn't compiling.

#include<stdio.h> #include<stdlib.h>  void dobig(double *parr[5],int *len,double *big);  void main() {     double *big;     double arr[5]={1.00,2.321,3.54337,4.333333,5.5555555};     double *parr=&arr[5];     int size=sizeof(arr)/sizeof(int);     int *len=&size;     dobig(parr,len,big);     printf("the largest number %p/n",*big);     system("pause"); }  void dobig(double *parr,int *len,double *big) {     int i;     double pbig=*parr;     for(i=0;i>*len;i++)     {         if(pbig<*(parr+i))         {             pbig=*(parr+i);         }         *big=pbig;     } } 

here's problem:

double *parr=&arr[5]; 

arr has 5 elements. valid index range 0 - 4.

i have commented inside code problems:

#include<stdio.h> #include<stdlib.h>  void dobig(double *parr,int *len,double *big); // prototype didn't match. want         // pass pointer, not array of pointers.      int main(int argc, char *argv[]) // standard way write main()     {     double big;     double arr[5]={1.00,2.321,6.54337,4.333333,5.5555555};      double *parr=&arr[0]; // if want loop through array             //in dobig(), have pass pointer first element or             //char   *parr=arr; fine.      int size=sizeof(arr)/sizeof(double); // want know how many double's                    // there in array. use sizeof(double)     int *len=&size;     dobig(parr,len,&big);     printf("the largest number %f\n",big); // print double,                                     //use %f. %p pointer.     }      void dobig(double *parr,int *len,double *big)     {     int i;     double pbig=*parr;     for(i=0;i<*len;i++)  // here doesn't enter                 // loop @ due incorrect condition.     {         if(pbig<*(parr+i))         {            pbig=*(parr+i);         }     }     *big=pbig;     }