sql - eleminating the records on cross row element - 


srid    interaction flag    flag2   items1                     items2 16222   abc b   4   1852311000001100    19836811000001100 16222   abc b   4   19836811000001100   1852311000001100 18599   abc b   4   1852311000001100    10368611000001100 18599   abc b   4   10368611000001100   1852311000001100 19518   abc   2   1592311000001100    1852311000001100 19518   abc   2   1852311000001100    1592311000001100 19518   abc   2   1852311000001100    19836811000001100 19518   abc   2   19836811000001100   1852311000001100

hi , above result set of complex query. till here able achieve.

please have on first 2 records. item1 of 1st row = item2 of 2nd row , vise versa srid.if item1 , item2 srid same in order , need 1 record itand result should be

 srid    interaction    flag    flag2   items1                     items2     16222   abc b   4   1852311000001100    19836811000001100     18599   abc b   4   1852311000001100    10368611000001100     19518   abc   2   1852311000001100    1592311000001100     19518   abc   2   1852311000001100    19836811000001100

depends on rest of data like, might work....

with sourcedata (     select      *     (  values   (16222, 'abc', 'b', 4, 1852311000001100, 19836811000001100)                     ,(16222, 'abc', 'b', 4, 19836811000001100, 1852311000001100)                     ,(18599, 'abc', 'b', 4, 1852311000001100, 10368611000001100)                     ,(18599, 'abc', 'b', 4, 10368611000001100, 1852311000001100)                     ,(19518, 'abc', 'a', 2, 1592311000001100, 1852311000001100)                     ,(19518, 'abc', 'a', 2, 1852311000001100, 1592311000001100)                     ,(19518, 'abc', 'a', 2, 1852311000001100, 19836811000001100)                     ,(19518, 'abc', 'a', 2, 19836811000001100, 1852311000001100)) tab(srid, interaction, flag, flag2, items1, items2) ) ,cte (     select distinct      s1.*     sourcedata s1     join sourcedata s2     on s1.srid=s2.srid     , s1.items1=s2.items2 ) ,cte2 (     select      *     ,row_number() over(partition srid order srid)%2 rowid     cte ) select  srid ,interaction ,flag ,flag2 ,items1 ,items2 cte2 rowid=1;

Comments

Post a Comment

Popular posts from this blog

c# - Send Image in Json : 400 Bad request -

from android trying send image class of data, iis webservice. (c#) the problem 400 bad request . the image being encoded base64 . , placed json rest of class elements. my guess base64 not valid inside json. server not understand it. if set string "" , post accepted fine. so question is, how make base64 valid within json array? ( tried url.encode no success). or how should send image android webservice? gson gson = new gson(); string json = gson.tojson(record); // record has param { string base64photo } how big image? i'm pretty sure surpassing iis json size limit (default 4 mb). check http://geekswithblogs.net/frankw/archive/2008/08/05/how-to-configure-maxjsonlength-in-asp.net-ajax-applications.aspx or http://www.webtrenches.com/post.cfm/iis7-file-upload-size-limits good luck!
Read more

javascript - addthis share facebook and google+ url -

i attempting use addthis create simple url shares whichever current page user on when click share button. of right now, have twitter working. when user clicks, able see url populated in tweet box. when user clicks facebook or google+, url doesn't seem show in share box. <ul class="addthis_toolbox addthis_default_style "> <li><a class="addthis_button_facebook"><img src="/img/facebook-social.png" width="20" height="20" border="0" alt="share" /></a></li> <li><a class="addthis_button_twitter"><img src="/img/twitter-social.png" width="20" height="20" border="0" alt="share" /></a></li> <li><a class="addthis_button_google_plusone_share"><img src="/img/google-social.png" width="20" height="20" border="0" alt="s...
Read more

ios - Show keyboard with UITextField in the input accessory view -

i have buttona , when buttona clicked, want keyboard show uitextfield in inputaccessoryview. there way have keyboard show manually , set inputaccessoryview without having uitextfield initially? thanks. you cannot summon keyboard without object can become first responder. there 2 ways work around: subclass uiview , implement uikeyinput protocol in it. example: in .h file: @interface inputobject : uiview<uikeyinput> @property (nonatomic, copy) nsstring *text; @property (nonatomic, strong) uiview *inputaccessoryview; // must override inputaccessoryview , since it's readonly default @end in .m file, implement protocol: - (bool)canbecomefirstresponder { return yes; } - (bool)hastext { return [self.text length]; } - (void)inserttext:(nsstring *)text { nsstring *selftext = self.text ? self.text : @""; self.text = [selftext stringbyappendingstring:text]; [[nsnotificationcenter defaultcenter] postnotificationname:kinputobjec...
Read more