python - print arguments on function invocation -

wondering easiest way debug prints.

i looking though code , there functions use lot of generic text arguments inputs. looking easy way print line without having modify avoid getting typos or errors in there

simple example, line in code

somefunction('%s_somestring', variable,     '%s_morestrings' %someotherstring, somemorestring, someobject) 

so instead of checking

print 'somefunction('%s_somestring', %s, '%s_morestrings', 'someobject')  %                (someotherstring, variable, somemorestring) 

i looking way print that. tried writing function print string , eval it, not work way intend

somefunction('someotherstring_somestring', variable,                'somemorestring_morestrings', someobject) 

is there way that

here's simple implementation:

from functools import wraps  def prints_invocation(f):     @wraps(f)     def wrapped(*args):         print "%s(%s)" % (f.__name__, ', '.join(repr(a) in args))         return f(*args)     return wrapped 

>>> @prints_invocation ... def add(x, y): ...     return x + y >>> add(1, 2) add(1, 2) 3 

it trivial extend print kwargs , return values