c++ - How to gmock functions in the same class when they call each other -

suppose here case:

class base() {    virtual func1()=0;    virtual func2()=0;    virtual func3()=0; } class inheritance:public base {    virtual func1(){ func2(); func3() };    virtual func2(){ /* */ };    virtual func3(){ /* */ }; } 

now want unit test func1(), , mock func2() , func3();

so possible mock func2() , func3() while func1() knows call mock-func2() , mock-func3() , not call real func2() , func3()?

by way use class factory init class, real case may little more complicated

thanks~

it's possible describe, it's not pretty. 1 way of doing have mock derive concrete class instead of interface, , create subclass of mock dispatch method calls appropriate superclass depending on configuration member. example:

// class mockbase inherits baseimpl, in turn inherits // 'base' interface class dispatch : public mockbase { public:     void func1() {         return usemockfunc1 ? mockbase::func1() : baseimpl::func1();     }      bool usemockfunc1; }; 

however, requires yet class, mandates mock inherit concrete implementation rather interface, , make programmers want dig eyes out spoon. rather using kind of abomination, worthwhile review design of class you're testing, looking ways decompose separate objects, each of mocked individually.