Replacing comma with any special character in string using java Regex -

i want replace commas 1 special character (e.g "#") present inside double quotes in java.

below string :

string line="\"lee, rounded, neck, printed\",410.00,300.00,\"red , blue\",lee"; 

output :

"lee# rounded# neck# printed",410.00,300.00,"red # blue",lee 

i have tried :

public class str {     public static void main(string[] args) {         string line="\"lee, rounded, neck, printed\",410.00,300.00,\"red , blue\",lee";         string linedelimiter=",";         string templine=line;       if(templine!=null && templine.contains("\""))       {           pattern p=pattern.compile("(\".*?"+pattern.quote(linedelimiter)+".*?\")");           matcher m=p.matcher(templine);           if(m.find())           {               (int = 1; <= m.groupcount(); i++) {                   string temp=m.group(i);                   string temp1=temp;                   temp=temp.replaceall("(,)", " ## ");                   line=line.replaceall(pattern.quote(temp1),pattern.quote(temp));               }           }       } } } 

using above code able find first occurances of string present inside quotes not second one("red , blue").

following code should work:

string line="\"lee, rounded, neck, printed\",410.00,300.00,\"red , blue\",lee"; string repl = line.replaceall(",(?!(([^\"]*\"){2})*[^\"]*$)", "#"); system.out.println("replaced => " + repl); 

output:

"lee# rounded# neck# printed",410.00,300.00,"red # blue",lee 

explanation: regex means match comma if not followed number of double quotes. in other words match comma if inside double quotes.

ps: assuming there no unbalanced double quotes , there no case of escaped double quotes.