Iterate through list of intervals in Python and return odd and even values? -

i'm working on fragment of code homework assignment.

i want to:

1. get user input(n).
2. make list out of input(n) range.
3. iterate through list.
4. count odds , evens.
5. return odds , evens use in function

i stumped , far got:

def input():     n = eval(input("enter number: "))  def getodds(n):     odd_count = 0     even_count = 0     list_start = list[1]     list_cont = list[1:]      in range(n):         ## know i'll using ##                  if position % 2 == 0:                                 even_count = even_count+1     return even_count     return odd_count 

you want like:

def getoddevencount(n):     odd_count = 0     even_count = 0      elem in range(n):         if elem % 2 == 0: even_count += 1         else: odd_count += 1     return odd_count, even_count 

example usage :

odd_count, even_count = getoddevencount(10) print("odds:", odd_count, "evens:", even_count) 

outputs:

odds: 5 evens: 5 

note however, if you're returning counts, , not list of actual odd/even values, return value of function can computed trivially in o(1) time taking advantage of fact even integer n, return value (n/2, n/2), , odd integer n, return value (floor(n/2), floor(n/2) + 1)